The degree–sensitivity exponent

Description of constant

Let $f$ be a Boolean function on $n$ bits, i.e.

\[f:\{0,1\}^n \to \{0,1\}\]

with $n\ge 2$. For $x\in$ {0,1}^n and $1\le i\le n$, let $x^{(i)}$ be $x$ with the $i$-th bit flipped.

The (pointwise) sensitivity of $f$ at $x$ is

\[s(f)(x):=\sum_{i=1}^n |f(x)-f(x^{(i)})|,\]

and the (max) sensitivity is

\[s(f):=\max_{x\in\{0,1\}^n} s(f)(x).\]

Let $\deg(f)$ be the degree of the unique multilinear polynomial over $\mathbb{R}^{n}$ that agrees with $f$ on {0,1}^n.

Define the degree–sensitivity exponent

\[C_{37}:=\sup \frac{\log \ (s(f))}{\log (\deg(f))},\]

where the supremum ranges over all $n\geq 2$ and all Boolean functions $f$ on {0,1}^n with $\deg(f)>1$.

Equivalently, $C_{37}$ is the supremum over exponents $\alpha>0$ such that there exists a Boolean function $f$ of degree at least 2 with

\[s(f)\ge (\deg(f))^{\alpha}.\]

Known upper bounds

Bound Reference Comments
$2$ [NS1994], [T2013] One has $s(f)\le bs(f)$ and $bs(f)\le O(\deg(f)^2)$, giving an exponent upper bound $C_{37}\le 2$.
$2$ [P2021] Improves the constant factor in the quadratic bound: $bs(f)\le \deg(f)^2/(\sqrt{10}-2)$, hence $s(f)\le \deg(f)^2/(\sqrt{10}-2)\approx 0.8604\,\deg(f)^2$ (still exponent $2$).

Known lower bounds

Bound Reference Comments
$1$ Trivial Parity on $n$ bits has $s(f)=n$ and $\deg(f)=n$.
$\log_2 3 \approx 1.58496$ [BdW2002], [T2013] Earlier explicit separation (pre-Kushilevitz)
$\log_3 6 \approx 1.63093$ [HKP2011] Kushilevitz function $h$ on $6$ bits has $s(h)=6$ and $\deg(h)=3$, and hence exponent $\log_3 6$.

$g(x_1,x_2,x_3)=x_1+x_2+x_3-x_1x_2-x_1x_3-x_2x_3,$

which is Boolean on the cube, has $\deg(g)=2$, and $s(g)=3$ at $x=(0,0,0)$.

References