Centered Hardy–Littlewood maximal constant in dimension $2$

Description of constant

In $\mathbb{R}^d$ ($d\ge 1$), let $M_d$ denote the centered Hardy–Littlewood maximal operator associated to cubes, defined by

\[M_d f(x)\ :=\ \sup_{r>0}\ \frac{1}{\lvert Q(x,r)\rvert}\int_{Q(x,r)} \lvert f(y)\rvert\,dy,\]

where $Q(x,r)$ is a closed $\ell_\infty$ ball of radius $r$ and center $x$ in $\mathbb{R}^d$, that is, a closed cube centered at $x$, with sides parallel to the coordinate axes, and sidelength $2r$, and $\lvert\cdot\rvert$ denotes Lebesgue measure. [Ald2011-def-Md] [Ald2011-def-Qxr]

Let $c_d$ be the smallest constant such that for every $f\in L^1(\mathbb{R}^d)$ and every $\alpha>0$,

\[\alpha\,\bigl\lvert\{x\in\mathbb{R}^d:\ M_d f(x)\ge \alpha\}\bigr\rvert\ \le\ c_d\,\lVert f\rVert_1.\]

[Ald2011-def-cd]

We define

\[C_{47}\ :=\ c_2,\]

the optimal weak-type $(1,1)$ constant of the centered Hardy–Littlewood maximal operator associated to axis-parallel squares in $\mathbb{R}^2$.

Known upper bounds

Bound Reference Comments
$9$ [Tao2006] The standard covering-lemma proof gives an explicit constant $3^d$ in the weak-type $(1,1)$ inequality, and the same argument applies to cubes; hence $c_2\le 3^2=9$. [Tao2006-weak-3d] [Tao2006-cubes]

Known lower bounds

Bound Reference Comments
$\dfrac{11+\sqrt{61}}{12}\approx 1.5675208$ [Mel2003], [Ald2011] Melas proved $c_1=\dfrac{11+\sqrt{61}}{12}$. Since $c_{d+1}\ge c_d$, we get $c_2\ge c_1$. [Mel2003-c1-formula] [Ald2011-monotone]

References

Contribution notes

Prepared with assistance from ChatGPT 5.2 Pro.