One-dimensional convex sub-Gaussian comparison constant

Description of constant

Let $X$ be an integrable real random variable. We say that $X$ is $1$-sub-Gaussian in the tail sense if \(\mathbf{E}[X]=0 \quad\text{and}\quad \mathbf{P}(\lvert X\rvert>t)\le 2e^{-t^2/2}\quad\text{for all }t\ge 0.\) [DP2026-abs-solved] [DP2026-def-tail]

For real random variables $X,Y$, write $X\preceq_{cx}Y$ if \(\mathbf{E}[f(X)]\le \mathbf{E}[f(Y)]\) for every convex $f:\mathbf{R}\to\mathbf{R}$ for which both expectations are finite. [DP2026-def-constant]

Let $G\sim\mathcal{N}(0,1)$ be standard normal. We define \(C_{48}:=\inf\Bigl\{C>0:\ \forall\ \text{$1$-sub-Gaussian }X,\ X\preceq_{cx}\sqrt{C}\,G\Bigr\}.\) [DP2026-def-constant]

Davis and Power proved that this one-dimensional problem is solved: if $c_\star$ denotes the sharp comparison factor, then $C_{48}=c_\star^2=c_0^2$, where $c_0$ is determined by an explicit system of one-dimensional equations. Numerically, \(C_{48}=c_0^2 \approx 5.33386.\) [DP2026-abs-solved] [DP2026-thm1-sharp] [DP2026-rem2-num]

Known upper bounds

Bound Reference Comments
$<\infty$ [vH25] Historical finiteness bound: van Handel proved that a universal Gaussian comparator exists in every dimension. [vH25-thm11]
$c_0^2 \approx 5.33386$ [DP2026] Solves the one-dimensional problem exactly. [DP2026-thm1-sharp] [DP2026-rem2-num]

Known lower bounds

Bound Reference Comments
$1$ Elementary Taking $X\sim\mathcal{N}(0,1)$ and testing with $f(x)=x^2$ gives $1=\mathbf{E}[X^2]\le \mathbf{E}[Z^2]=C$, so any admissible $C$ must satisfy $C\ge 1$.
$c_0^2 \approx 5.33386$ [DP2026] The sharpness part of Theorem 1 shows that no smaller constant works. [DP2026-thm1-sharp] [DP2026-rem2-num]

References