Favard-length decay exponent

Description of constant

Let $E\subset \mathbb{R}^2$ be a planar set. The Favard length of $E$ is defined by

\[\mathrm{Fav}(E)\ :=\ \frac{1}{\pi}\int_0^\pi \lvert \mathrm{Proj}\,R_\theta E\rvert\, d\theta,\]

where $\mathrm{Proj}$ is orthogonal projection to the horizontal axis and $R_\theta$ is rotation by angle $\theta$. [NPV2011-def-fav]

The Favard length has the following probabilistic interpretation: up to a constant factor, $\mathrm{Fav}(E)$ is the probability that a “Buffon’s needle” (a long line segment dropped at random) hits $E$. [NPV2011-buffon-interpretation]

Let $C_n$ be the $n$-th stage in the construction of the middle-half Cantor set, and let

\[K_n\ :=\ C_n \times C_n.\]

Then $K_n$ is a union of $4^n$ axis-parallel squares of side length $4^{-n}$. [NPV2011-Kn-4n-squares]

A classical theorem of Besicovitch implies that $\mathrm{Fav}(K_n)\to 0$ as $n\to\infty$, and it remains open to determine the exact rate of decay. [NPV2011-besicovitch-open-decay]

We define the Favard-length decay exponent $\alpha_{\mathrm{Fav}}$ by

\[C_{60}\ :=\ \alpha_{\mathrm{Fav}}\ :=\ \sup\Bigl\{\alpha\ge 0:\ \exists C>0\ \text{such that}\ \mathrm{Fav}(K_n)\le C\,n^{-\alpha}\ \text{for all}\ n\in\mathbb{N}\Bigr\}.\]

The best established range currently is

\[\frac{1}{6}\ \le\ \alpha_{\mathrm{Fav}}\ \le\ 1.\]

[NPV2011-thm1-powerlaw] [BV2010-thm1-lb-logn-over-n]

Known upper bounds

Bound Reference Comments
$1$ [BV2010] Bateman–Volberg prove $\mathrm{Fav}(K_n)\ge c\,\frac{\log n}{n}$, which rules out any estimate $\mathrm{Fav}(K_n)\le C n^{-\alpha}$ with $\alpha>1$. [BV2010-thm1-lb-logn-over-n]

Known lower bounds

Bound Reference Comments
$0$   Trivial (since $\mathrm{Fav}(K_n)$ is uniformly bounded).
$1/6$ [NPV2011] Nazarov–Peres–Volberg prove $\mathrm{Fav}(K_n)\le C n^{-1/6+\delta}$ (equivalently, $\mathrm{Fav}(K_n)\le C n^{\delta-1/6}$) for every $\delta>0$. [NPV2011-thm1-powerlaw]

References

Contribution notes

Prepared with assistance from ChatGPT 5.2 Pro.