Selberg congruence spectral-gap constant

Description of constant

Let $\Gamma\subset SL_2(\mathbb{Z})$ be a congruence subgroup. Denote by $0=\lambda_0<\lambda_1(\Gamma)\le \lambda_2(\Gamma)\le \cdots$ the eigenvalues of the (non-Euclidean) Laplacian acting on $L^2(\Gamma\backslash\mathbb{H})$. [LRS1995-def-conjecture]

Selberg’s eigenvalue conjecture asserts that, for every congruence subgroup $\Gamma$, the smallest nonzero eigenvalue satisfies \(\lambda_1(\Gamma)\ \ge\ \frac14.\) [LRS1995-def-conjecture]

For a given $\Gamma$, define the gap parameter \(\theta(\Gamma)\ :=\ \sqrt{\max\Bigl(0,\frac14-\lambda_1(\Gamma)\Bigr)}.\)

We define \(C_{61}\ :=\ \sup_{\Gamma\ \text{congruence}}\ \theta(\Gamma).\) By construction, $C_{61}=0$ is equivalent to Selberg’s eigenvalue conjecture (no exceptional eigenvalues $\lambda_1(\Gamma)<1/4$ for congruence subgroups).

Selberg proved that congruence subgroups have no exceptional eigenvalues below $3/16$, i.e. \(\lambda_1(\Gamma)\ \ge\ \frac{3}{16},\) for congruence $\Gamma$. [LRS1995-selberg-316] Consequently, $C_{61}\le 1/4$.

Kim-Sarnak proved the sharper uniform bound \(\lambda_1(\Gamma)\ \ge\ \frac{975}{4096},\) so $C_{61}\le 7/64$ (since $975/4096 = 1/4-(7/64)^2$). [KRS2003-975-4096]

The best established range currently is \(0\ \le\ C_{61}\ \le\ \frac{7}{64}.\)

Known upper bounds

Bound Reference Comments
$1/4$ [LRS1995] From Selberg’s theorem $\lambda_1(\Gamma)\ge 3/16$ for congruence $\Gamma$. [LRS1995-selberg-316]
$7/64$ [KRS2003] Derived from the uniform bound $\lambda_1(\Gamma)\ge 975/4096$. [KRS2003-975-4096]

Known lower bounds

Bound Reference Comments
$0$   Trivial from the definition $C_{61}\ge 0$.

References

Contribution notes

Prepared with assistance from ChatGPT 5.2 Pro.