Erdős unit distance exponent

Description of constant

For a finite set $P \subset \mathbb{R}^2$ of $n$ points, let \(u(P) := \lvert \\{ \\{x,y\\} \subset P : \lvert x-y \rvert = 1 \\} \rvert\) denote the number of unordered pairs of points in $P$ at unit distance, and let $u(n) := \max_{\lvert P\rvert = n} u(P)$ denote the maximum number of unit distances among any set of $n$ points in the plane. The Erdős unit distance exponent is \(C_{84} := \limsup_{n \to \infty} \frac{\log u(n)}{\log n}.\) Equivalently, $C_{84}$ is the infimum of all $\alpha$ for which $u(n) \ll_\alpha n^\alpha$ as $n \to \infty$.

The problem was introduced by Erdős in 1946 [E1946], who conjectured that $u(n) = n^{1+o(1)}$, i.e. $C_{84} = 1$. This conjecture was disproved in May 2026 by an OpenAI internal model [O2026], with a human-verified writeup given in [ABGLSSTWW2026]; an explicit improved lower bound was obtained shortly afterwards by Sawin [S2026].

Known upper bounds

Bound Reference Comments
$3/2$ [E1946] Erdős’ original argument, based on the observation that the unit-distance graph contains no $K_{2,3}$.
$4/3 = 1.333\dots$ [SST1984] Spencer, Szemerédi and Trotter; via the Szemerédi–Trotter incidence theorem.

Known lower bounds

Bound Reference Comments
$1$ [E1946] A $\sqrt{n} \times \sqrt{n}$ portion of the integer lattice gives $u(n) \gg n^{1 + c/\log\log n}$, hence $\limsup \log u(n)/\log n \geq 1$. Conjectured by Erdős to be sharp.
$> 1$ (inexplicit) [O2026], [ABGLSSTWW2026] An OpenAI internal reasoning model produced a (one-shot) construction giving $u(n) \gg n^{1+\varepsilon}$ for some $\varepsilon > 0$ and infinitely many $n$, disproving Erdős’ conjecture. The construction is number-theoretic, using algebraic number fields of large degree and small discriminant via a Golod–Shafarevich argument. A particular parameter choice in [ABGLSSTWW2026] yields the explicit value $\varepsilon \approx 6.24 \cdot 10^{-38}$.
$1.014$ [S2026] Sawin, by optimizing the Golod–Shafarevich step and the choice of number field.
$1.03184\dots$ [EPF90] mlewko, posted on the Erdős Problems forum (21 May 2026); reuses Sawin’s argument with optimized finite data ($\lvert T\rvert = 74$, $\lvert S\rvert = 1082$) produced by ChatGPT 5.5 Pro. Unverified.
$1.03188\dots$ [MO511514] spiderduckpig, posted on MathOverflow (21 May 2026); replaces the primes $347,353$ in mlewko’s $T$ by $503,601$. Unverified.
$1.03190\dots$ [MO511514] spiderduckpig, MathOverflow comment (22 May 2026); further replaces $337,349,373$ in $T$ by $389,443,587$. Unverified.
$1.0333487\dots$ [MO511514] spiderduckpig, MathOverflow comment (22 May 2026); claimed via a weighted-Zassenhaus-filtration modification of Sawin’s Lemma 11, so requires a change to the proof structure and not just finite data. Unverified.
$1.03447\dots$ [MO511514] Naslund, MathOverflow answer (22 May 2026); combines spiderduckpig’s Golod–Shafarevich refinement with three further structural improvements to Sawin’s argument — a Louboutin-style bound on $L(1,\chi)$ via $\zeta_{E_T}$, a sphere-overlap refinement of Lemmas 4–5, and a narrow-class-group sharpening of Lemma 7 — then re-optimizes $T$ (the first $51$ odd primes minus $\{227,233\}$). Hybrid ChatGPT 5.5 Pro / human work. Unverified.
$1.0346749\dots$ [MO511514] Naslund, revised (≈24 May 2026); corrects the optimization to fully include the narrow-class-group improvement, with optimizer $\lvert T\rvert = 48$. (An intermediate $T$-tweak had given $1.03448\dots$.) Unverified.
$1.03158935$ [MO511514] Tseng, MathOverflow answer (25 May 2026). Does not improve the record exponent, but supplies a reproducible pointwise certificate: $u(n) \geq \frac{1}{128 P_{89}} n^{1.03158935}$ for all sufficiently large $n$, where $P_{89}$ is the product of the first $89$ odd primes. Uses Sawin’s construction as a black box plus prime-ideal microselection, a fractional-knapsack model and a dyadic-circle covering certificate (repository). AI-assisted. Unverified.
$1.0346609571815997\dots$ [MO511514] spiderduckpig, revised answer (25 May 2026); a reproducible finite-data/certificate improvement. Does not exceed Naslund’s $1.0346749\dots$. Unverified.
$1.03583\dots$ [MO511514] Naslund, revised (≈25 May 2026); replaces the sphere-packing estimate by a covolume bound on the ideal lattice (asserted to be essentially optimal for this part of the argument), re-optimizing to $\lvert T\rvert = 39$. Hybrid ChatGPT 5.5 Pro / human work. Current best. Unverified.

References

Contribution notes

Prepared with assistance from Claude Opus 4.7, which retrieved abstracts of the May 2026 preprints and the OpenAI announcement. All references should be independently verified before citation.