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Analysis.Section_8_3

theorem Chapter8.Schroder_Bernstein_lemma {X : Type} {A B C : Set X} (hAB : A ⊆ B) (hBC : B ⊆ C) (f : ↑C ↪ ↑A) :
have D := fun (t : ℕ) => Nat.rec ((⇑f.image ∘ ⇑(B.embeddingOfSubset C hBC).image) {x : ↑B | ↑x ∉ A}) (fun (x : ℕ) => ⇑f.image ∘ ⇑(B.embeddingOfSubset C hBC).image ∘ ⇑(A.embeddingOfSubset B hAB).image) t; Set.univ.PairwiseDisjoint D ∧ have g := fun (x : ↑A) => if h : x ∈ ⋃ (n : ℕ), D n ∧ ∃ (y : ↑B), f ⟨↑y, ⋯⟩ = x then ⋯.choose else ⟨↑x, ⋯⟩; Function.Bijective g

Exercise 8.3.2. Some subtle type changes due to how sets are implemented in Mathlib. Also we shift the sequence D by one so that we can work in Set A rather than Set B.

@[reducible, inline]
abbrev Chapter8.LeCard (X Y : Type) :
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    theorem Chapter8.Schroder_Bernstein {X Y : Type} (hXY : LeCard X Y) (hYX : LeCard Y X) :

    Exercise 8.3.3

    @[reducible, inline]
    abbrev Chapter8.LtCard (X Y : Type) :
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      @[reducible, inline]
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