Analytic Number Theory Exponent Database

8 Large value theorems for zeta partial sums

Now we study a variant of the exponent LV(σ,τ), specialized to the Riemann zeta function.

Definition 8.1 Large value zeta exponent
#

Let 1/2σ1 and τ0 be fixed. We define LVζ(σ,τ)[,+) to be the least (fixed) exponent for which the following claim is true: if (N,T,V,(an)n[N,2N],J,W) is a zeta large value pattern with N is unbounded, T=Nτ+o(1), and V=Nσ+o(1), then |W|Nρ+o(1).

Implemented at large_values.py as:
Large_Value_Estimate

We will primarily be interested in the regime τ2 (as this is the region connected to the Riemann-Siegel formula for ζ(σ+it)), but for sake of completeness we develop the theory for the entire range τ0. (The range 0τ1 can be worked out exactly by existing tools, while the region 1<τ<2 can be reflected to the region 2<τ< by Poisson summation.)

As usual, we have a non-asymptotic formulation of LVζ(σ,τ):

Lemma 8.2 Asymptotic form of large value exponent at zeta

Let 1/2σ1, τ0, and ρ0 be fixed. Then the following are equivalent:

  • LVζ(σ,τ)ρ.

  • For every ε>0 there exists C,δ>0 such that if (N,T,V,(an)n[N,2N],J,W) is a zeta large value pattern with N>C, NτδTNτ+δ, and NσδVNσ+δ, then one has

    |W|CNρ+ε.

The proof of Lemma 8.2 proceeds as in previous sections and is omitted.

Lemma 8.3 Basic properties
  • (Monotonicity in σ) For any τ0, σLVζ(σ,τ) is upper semicontinuous and monotone non-increasing.

  • (Trivial bound) For any 1/2σ1 and τ0, we have LVζ(σ,τ)τ.

  • (Domination by large values) We have LVζ(σ,τ)LV(σ,τ) for all 1/2σ1 and τ0.

  • (Reflection) For 1/2σ1 and τ>1, one has

    supσσ1LVζ(12+1τ1(σ12),ττ1)+1τ1(σσ)=1τ1supσσ1(LVζ(σ,τ)+σσ).

Implemented at zeta_large_values.py as:
get_trivial_zlv()

We note that in practice, bounds for LVζ(σ,τ)+σ are monotone decreasing 1 in σ, so the reflection property in Lemma 8.3(iv) morally simplifies 2 to

LVζ(12+1τ1(σ12),ττ1)=1τ1LVζ(σ,τ).
1

TODO: implement a python method for reflection

Proof

Note in comparison with LV(σ,τ), that LVζ(σ,τ) can be , and is indeed conjectured to do so whenever σ>1/2 and τ1. Indeed:

Lemma 8.4 Characterization of negative infinite value

Let 1/2σ1 and τ0 be fixed. Then the following are equivalent:

  • LVζ(σ,τ)=.

  • LVζ(σ,τ)<0.

  • There exists a fixed ε>0 such that if N is unbounded and I is a subinterval of [N,2N], then one has

    nInitNσε+o(1)

    whenever |t|=Nτ+o(1).

Proof
Corollary 8.5

If τ0 is fixed then LVζ(σ,τ)= whenever σ>τβ(1/τ) is fixed. For instance, by 8, one has LVζ(σ,1)= whenever σ>1/2 is fixed.

Proof

If τ>0 and 1/2σ01 are fixed, then LVζ(σ,τ)= whenever σ>σ0+τμ(σ0).

Proof

If (k,) is an exponent pair, then LVζ(σ,τ)= whenever 1/2σ1, τ0 are fixed quantities with σ>kτ+k.

Proof
Corollary 8.8

Assuming the Lindelof hypothesis, one has LVζ(σ,τ)= whenever σ>1/2 and τ1.

Proof

For completeness, we now work out the values of LVζ(σ,τ) in the remaining cases not covered by the above corollary.

Lemma 8.9 Value at σ=1/2

One has LVζ(1/2,τ)=τ for all τ1.

Proof
Lemma 8.10 Value at τ<1

If 0τ<1, then LVζ(σ,τ) is equal to for σ>1τ and equal to τ for σ1τ.

Proof

One can use exponent pairs to control LVζ(σ,τ):

Lemma 8.11 From exponent pairs to zeta large values estimate

[ 110 , Theorem 8.2 ] If (k,) is an exponent pair with k>0, then for any 1/2σ1 and τ0 one has

LVζ(σ,τ)max(τ6(σ1/2),k+kτ2(1+2k+2)k(σ1/2)).

By applying this lemma to the exponent pairs in Corollary 5.11, one recovers the bounds in [ 110 , Corollary 8.1, 8.2 ] (up to epsilon losses in the exponents).

A useful connection between large values estimates and large values estimates for the zeta function is the following strengthening of Theorem 7.10.

Lemma 8.12 Halász–Montgomery inequality

For any 1/2σ1 and τ0, we have

LV(σ,τ)max(22σ,12σ+supmax(1/2,2σ1)σ11ττσ+LVζ(σ,τ)).

Note from Lemma 8.5 one could also impose the restriction στβ(1/τ) in the supremum if desired, at which point one recovers Theorem 7.10. Similarly, from Corollary 8.6 one could also impose the restriction σσ0+τμ(σ0) for any fixed 1/2σ01.

Proof
Corollary 8.13 Converting a bound on μ to a large values theorem

If 1/2σ1, σ1, and τ0 are fixed, then

LV(σ,τ)max(22σ,22σ+τ2σ1σμ(σ)).

In particular, the Montgomery conjecture holds for τ2σ1σμ(σ).

Proof
Theorem 8.14 Halász-Turán large values theorem

[ 63 , Theorem 1 ] On the Lindelöf hypothesis, one has the Montgomery conjecture whenever σ>3/4.

Proof
Theorem 8.15 First Ivic large values theorem

[ 110 , Lemma 8.2 ] If τ0 and 1/2<σ<σ<1 are fixed, then

LV(σ,τ)max(22σ,τf(σ)(σσ))

where f(σ) is equal to

234σ for 1/2<σ2/3;1078σ for 2/3σ11/14;341516σ for 11/14σ13/15;983132σ for 13/15σ57/62;51σ for 57/62σ<1.

In particular, the Montgomery conjecture holds for this choice of σ if

τsup1/2<σ<σf(σ)(σσ)+22σ.
Proof

Another typical application of the Halász-Montgomery inequality is

Lemma 8.16 Second Ivic large values theorem

[ 110 , (11.40) ] For any 1/2σ1 and τ0, one has

LV(σ,τ)max(22σ,τ+912σ,3τ+19(34σ)/2).

In particular, optimizing using subdivision (Lemma 7.7) we have

LV(σ,τ)max(22σ,τ+912σ,τ84σ656).

This implies the Montgomery conjecture for

τmin(10σ7,12σ536).
Proof
  1. This reflects the fact that large value theorems usually relate to pth moment bounds for p1 (e.g., p=2,4,6,12) rather than for 0<p<1.
  2. Alternatively, one can redefine LVζ to use smooth cutoffs in the n variable rather than rough cutoffs 1I(n), in which case one can obtain the analogue of 1 rigorously, but we will not do so here.