Polynomial Freiman-Ruzsa conjecture #
Here we prove the polynomial Freiman-Ruzsa conjecture.
Given two independent random variables U
and V
uniformly distributed respectively on A
and B
, then U = V
with probability #(A ∩ B) / #A ⬝ #B
.
Given two independent random variables U
and V
uniformly distributed respectively on A
and B
, then U = V + x
with probability # (A ∩ (B + x)) / #A ⬝ #B
.
A uniform distribution on a set with doubling constant K
has self Rusza distance
at most log K
.
Auxiliary statement towards the polynomial Freiman-Ruzsa (PFR) conjecture: if A
is a subset of
an elementary abelian 2-group of doubling constant at most $K$, then there exists a subgroup H
such that A
can be covered by at most K^(13/2) |A|^(1/2) / |H|^(1/2)
cosets of H
, and H
has
the same cardinality as A
up to a multiplicative factor K^11
.
The polynomial Freiman-Ruzsa (PFR) conjecture: if A
is a subset of an elementary abelian
2-group of doubling constant at most K
, then A
can be covered by at most 2 * K ^ 12
cosets of
a subgroup of cardinality at most |A|
.
Corollary of PFR_conjecture
in which the ambient group is not required to be finite (but) then
H
and c
are finite.