Polynomial Freiman-Ruzsa conjecture #
Here we prove the polynomial Freiman-Ruzsa conjecture.
Given two independent random variables U and V uniformly distributed respectively on A
and B, then U = V with probability #(A ∩ B) / #A ⬝ #B.
Given two independent random variables U and V uniformly distributed respectively on A
and B, then U = V + x with probability # (A ∩ (B + x)) / #A ⬝ #B.
A uniform distribution on a set with doubling constant K has self Rusza distance
at most log K.
Auxiliary statement towards the polynomial Freiman-Ruzsa (PFR) conjecture: if A is a subset of
an elementary abelian 2-group of doubling constant at most $K$, then there exists a subgroup H
such that A can be covered by at most K^(13/2) |A|^(1/2) / |H|^(1/2) cosets of H, and H has
the same cardinality as A up to a multiplicative factor K^11.
The polynomial Freiman-Ruzsa (PFR) conjecture: if A is a subset of an elementary abelian
2-group of doubling constant at most K, then A can be covered by at most 2 * K ^ 12 cosets of
a subgroup of cardinality at most |A|.
Corollary of PFR_conjecture in which the ambient group is not required to be finite (but) then
H and c are finite.